What is the slope ofintercept y+3=-1/3 (x+1) ?

The slope ofintercept y+3=-1/3 (x+1) is y=-1/3 x-10/3

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slope ofintercept y+3=-1/3 (x+1)

slope intercept

y + 3 = - \frac{1}{3} (x + 1)

y = - \frac{1}{3} x - \frac{10}{3}

Solution steps

y + 3 = - \frac{1}{3} (x + 1)

Convert to slope intercept form:

y = - \frac{1}{3} x - \frac{10}{3}

For a line in the form of

y = mx + b

, the slope is

m

and

y

intercept is

b

y = - \frac{1}{3} x - \frac{10}{3}

2

f (x) = \frac{2 x ^{2}}{x ^{2} - 4}

sin (6 x)

f (x) = x^{3} + 2 x^{2} + x - 7

f (x) = x^{2} - 4

What is the slope ofintercept y+3=-1/3 (x+1) ?
The slope ofintercept y+3=-1/3 (x+1) is y=-1/3 x-10/3