What is the domain of f(x)=\sqrt[4]{x+8} ?

The domain of f(x)=\sqrt[4]{x+8} is x>=-8

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domain of f(x)=\sqrt[4]{x+8}

domain

x \geq - 8

Interval Notation

[- 8, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 8

The function domain

x \geq - 8

f (x) = \frac{1}{4 x - 20}

f (x) = 10 x - 1

f (x) = - x^{5}

8 x - 3 y = - 5

(- 3.5) (0.8)

What is the domain of f(x)=\sqrt[4]{x+8} ?
The domain of f(x)=\sqrt[4]{x+8} is x>=-8