What is the shift 7cos(10x-6pi)+8 ?

The shift 7cos(10x-6pi)+8 is Phase:(3pi)/5 , Vertical:8

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shift 7cos(10x-6pi)+8

shift

7 cos (10 x - 6 π) + 8

Phase : \frac{3 π}{5}, Vertical : 8

Solution steps

f (x) = 7 cos (10 x - 6 π) + 8

g (B x - C) = cos (10 x - 6 π), B = 10, C = 6 π, D = 8

Therefore, the phase shift

\frac{C}{B}

\frac{6 π}{10}

\frac{3 π}{5}

The vertical shift

D

8

8

\frac{x}{x + 7}

s^{3}

\frac{x}{x + 1}

\frac{7 x - 4 y}{4} = x + 2

\frac{x ^{2} - 2}{x ^{2} - x - 2}

What is the shift 7cos(10x-6pi)+8 ?
The shift 7cos(10x-6pi)+8 is Phase:(3pi)/5 , Vertical:8