What is the inverse of f(x)=-(x+1)^2-3 ?

The inverse of f(x)=-(x+1)^2-3 is sqrt(-x-3)-1,-sqrt(-x-3)-1

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inverse of f(x)=-(x+1)^2-3

inverse

f (x) = - (x + 1)^{2} - 3

- x - 3 - 1, - - x - 3 - 1

Solution steps

y = - (x + 1)^{2} - 3

Replace

x

with

y

x = - (y + 1)^{2} - 3

Solve for

y, x = - (y + 1)^{2} - 3

- x - 3 - 1, - - x - 3 - 1

\frac{x - 1}{x ^{2} - x - 12}

- 2 sin (\frac{x}{2} - \frac{π}{3}) + 5

f (x) = \frac{x ^{2} + x - 2}{x ^{2}}

f (x) = \frac{x - 4}{3 x + 5}

cos (4 x)

What is the inverse of f(x)=-(x+1)^2-3 ?
The inverse of f(x)=-(x+1)^2-3 is sqrt(-x-3)-1,-sqrt(-x-3)-1