What is the extreme f(x)=x^3-27x+1 ?

The extreme f(x)=x^3-27x+1 is Maximum(-3,55),Minimum(3,-53)

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extreme f(x)=x^3-27x+1

extreme points

f (x) = x^{3} - 27 x + 1

Maximum (- 3, 55), Minimum (3, - 53)

Solution steps

f^{'} (x) = 3 x^{2} - 27

Find intervals:

Increasing

: - \infty < x < - 3,

Decreasing

: - 3 < x < 3,

Increasing

: 3 < x < \infty

Plug

x = - 3

into

x^{3} - 27 x + 1 : 55

Maximum (- 3, 55)

Plug

x = 3

into

x^{3} - 27 x + 1 : - 53

Minimum (3, - 53)

Maximum (- 3, 55), Minimum (3, - 53)

6 x - 2 y = 18

f (x) = \frac{1}{x - 4} - 2

f (x) = \frac{10}{4 - x}

f (x) = \frac{24}{x + 3}

f (x) = \frac{- x ^{2}}{x ^{2} - 2 x + 8}

What is the extreme f(x)=x^3-27x+1 ?
The extreme f(x)=x^3-27x+1 is Maximum(-3,55),Minimum(3,-53)