What is the domain of f(x)=(4x^2-9)/(4x^2-4x-3) ?

The domain of f(x)=(4x^2-9)/(4x^2-4x-3) is x 3/2

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domain of f(x)=(4x^2-9)/(4x^2-4x-3)

domain

f (x) = \frac{4 x ^{2} - 9}{4 x ^{2} - 4 x - 3}

x < - \frac{1}{2} or - \frac{1}{2} < x < \frac{3}{2} or x > \frac{3}{2}

Interval Notation

(- \infty, - \frac{1}{2}) \cup (- \frac{1}{2}, \frac{3}{2}) \cup (\frac{3}{2}, \infty)

Solution steps

Find undefined (singularity) points:

x = \frac{3}{2}, x = - \frac{1}{2}

The function domain

x < - \frac{1}{2} or - \frac{1}{2} < x < \frac{3}{2} or x > \frac{3}{2}

f (x) = x^{3} - 6 x^{2} + 13

f (x) = 7 x - 2 y = - 2

g (x) = 4 x + 48

x^{3} - 6 x^{2} + 9 x

f (x) = - x^{3} + 3

What is the domain of f(x)=(4x^2-9)/(4x^2-4x-3) ?
The domain of f(x)=(4x^2-9)/(4x^2-4x-3) is x<-1/2 \lor-1/2 <x< 3/2 \lor x> 3/2