What is the parity y=(1/(x+1/3+Ce^{3x)})^{1/3} ?

The parity y=(1/(x+1/3+Ce^{3x)})^{1/3} is Neither even nor odd

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parity y=(1/(x+1/3+Ce^{3x)})^{1/3}

parity

y = (\frac{1}{x + \frac{1}{3} + C e ^{3 x}})^{\frac{1}{3}}

Neither even nor odd

Solution steps

f (x) : (\frac{3}{3 x + 1 + 3 C e ^{3 x}})^{\frac{1}{3}}

f (- x) : (\frac{3}{- 3 x + 1 + 3 C e ^{- 3 x}})^{\frac{1}{3}}

- f (x) : - (\frac{3}{3 x + 1 + 3 C e ^{3 x}})^{\frac{1}{3}}

Check parity of

(\frac{3}{3 x + 1 + 3 C e ^{3 x}})^{\frac{1}{3}}

Check if Even:

False

Check if Odd:

False

Neither even nor odd

f (x) = \frac{7 x}{x ^{2} - 2 x - 3}

f (x) = 7 (x + 5)^{3} - 6

\frac{2}{x ^{2} - 2 x - 3}

3 (x - 1)^{2} - 2

What is the parity y=(1/(x+1/3+Ce^{3x)})^{1/3} ?
The parity y=(1/(x+1/3+Ce^{3x)})^{1/3} is Neither even nor odd