What is the inverse of f(x)=11cos(2x)+5 ?

The inverse of f(x)=11cos(2x)+5 is (arccos((x-5)/(11)))/2

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inverse of f(x)=11cos(2x)+5

inverse

f (x) = 11 cos (2 x) + 5

\frac{arccos ( \frac{x - 5}{11} )}{2}

Solution steps

Solve for

cos (2 x), y = 11 cos (2 x) + 5

cos (2 x) = \frac{y - 5}{11}

cos (a) = b \Rightarrow a = arccos (b)

2 x = arccos (\frac{y - 5}{11})

Solve for

x, 2 x = arccos (\frac{y - 5}{11})

\frac{arccos ( \frac{y - 5}{11} )}{2}

Substitute

y = x

\frac{arccos ( \frac{x - 5}{11} )}{2}

(1, 5), (7, - 1)

3 x^{3} + 7 x - 3

f (x) = 6 sin (3 x - π)

f (x) = (10 - 4 e^{- x})

What is the inverse of f(x)=11cos(2x)+5 ?
The inverse of f(x)=11cos(2x)+5 is (arccos((x-5)/(11)))/2