What is the perpendicular y=-2x+8 ?

The perpendicular y=-2x+8 is y= 1/2 x+b

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perpendicular y=-2x+8

perpendicular

y = - 2 x + 8

y = \frac{1}{2} x + b

Solution steps

Find the slope of

y = - 2 x + 8 : m = - 2

Compute the slope of the perpendicular line:

m_{p} = \frac{1}{2}

Line with slope m=

\frac{1}{2} : y = \frac{1}{2} x + b

y = \frac{1}{2} x + b

f (x) = 3 x^{2} - 18 x + 26

Y (x) = - \frac{1}{3} x + 6, (- 6, 0)

f (x) = 2 x^{3} - 2 x^{2} - 7 x + 3

f (x) = \frac{( 2 x ^{2} )}{( x ^{2} + 5 x + 4 )}

sin (t) - (cos (t) + sin (t))