What is the range of 3+(8+x)^{1/2} ?

The range of 3+(8+x)^{1/2} is f(x)>= 3

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range of 3+(8+x)^{1/2}

range

3 + (8 + x)^{\frac{1}{2}}

f (x) \geq 3

Interval Notation

[3, \infty)

Solution steps

The range of an radical function of the form

c a x + b + k

f (x) \geq k

k = 3

f (x) \geq 3

f (x) = \frac{2}{6 x ^{2} + 13 x - 5}

3 cos (4 x)

(6.8) (10.4)

\frac{- 3 x ^{2} - 12 x - 9}{x ^{2} + 5 x + 4}

49 - x^{2}