What is the inverse of f(x)=80-4.9t^2 ?

The inverse of f(x)=80-4.9t^2 is sqrt(-(10t-800)/(49)),-sqrt(-(10t-800)/(49))

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inverse of f(x)=80-4.9t^2

inverse

f (x) = 80 - 4.9 t^{2}

- \frac{10 t - 800}{49}, - - \frac{10 t - 800}{49}

Solution steps

x = 80 - 4.9 t^{2}

Replace

t

with

x

t = 80 - 4.9 x^{2}

Solve for

x, t = 80 - 4.9 x^{2}

- \frac{10 t - 800}{49}, - - \frac{10 t - 800}{49}

\frac{4 x ^{2} + 1}{2 x ^{2} + 5 x - 3}

y = 4 cos (π x + \frac{π}{2})

\frac{x + 2}{x}

y = (x - 1)^{2} + 2

f (x) = \frac{6}{x - 5}

What is the inverse of f(x)=80-4.9t^2 ?
The inverse of f(x)=80-4.9t^2 is sqrt(-(10t-800)/(49)),-sqrt(-(10t-800)/(49))