What is the domain of f(x)=9+(4+x)^{1/2} ?

The domain of f(x)=9+(4+x)^{1/2} is x>=-4

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domain of f(x)=9+(4+x)^{1/2}

domain

f (x) = 9 + (4 + x)^{\frac{1}{2}}

x \geq - 4

Interval Notation

[- 4, \infty)

Solution steps

Find non-negative values for radicals:

x \geq - 4

The function domain

x \geq - 4

f (x) = \frac{x + 3}{x}

f (x) = \frac{12 x ^{2} + 3}{3 x ^{2} - 2 x + 1}

f (x) = 3 x^{2} + 4 x + 1

f (x) = - 3 x - 3

\frac{x + 2}{x ^{2} - 3 x - 10}

What is the domain of f(x)=9+(4+x)^{1/2} ?
The domain of f(x)=9+(4+x)^{1/2} is x>=-4