What is the shift y=-4sin(6x+pi/2) ?

The shift y=-4sin(6x+pi/2) is Phase:-pi/(12), Vertical:0

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shift y=-4sin(6x+pi/2)

shift

y = - 4 sin (6 x + \frac{π}{2})

Phase : - \frac{π}{12}, Vertical : 0

Solution steps

f (x) = - 4 sin (6 x + \frac{π}{2})

g (B x - C) = sin (6 x + \frac{π}{2}), B = 6, C = - \frac{π}{2}, D = 0

Therefore, the phase shift

\frac{C}{B}

\frac{- \frac{π}{2}}{6}

- \frac{π}{12}

The vertical shift

D

0

0

f (x) = \frac{x}{x ^{2} + 5}

f (x) = - x^{2} + 1

f (x) = - x

\frac{x ^{2} - 2 x - 15}{2 x ^{2} + 7 x + 3}

sin (x - \frac{π}{4})

What is the shift y=-4sin(6x+pi/2) ?
The shift y=-4sin(6x+pi/2) is Phase:-pi/(12), Vertical:0