What is the domain of f(x)=(sqrt(x))/(3x^2+2x-1) ?

The domain of f(x)=(sqrt(x))/(3x^2+2x-1) is 0 1/3

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domain of f(x)=(sqrt(x))/(3x^2+2x-1)

domain

f (x) = \frac{x}{3 x ^{2} + 2 x - 1}

0 \leq x < \frac{1}{3} or x > \frac{1}{3}

Interval Notation

[0, \frac{1}{3}) \cup (\frac{1}{3}, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 0

Find undefined (singularity) points:

x = \frac{1}{3}, x = - 1

Combine real regions and undefined points for final function domain

0 \leq x < \frac{1}{3} or x > \frac{1}{3}

y = 3 sec (x) + 5

3 + lo g_{4} (x + 2)

3 x + \frac{27}{x}

m = - \frac{7}{2}, (- 4, - 5)

f (x) = x^{4} - 25 x^{2}

What is the domain of f(x)=(sqrt(x))/(3x^2+2x-1) ?
The domain of f(x)=(sqrt(x))/(3x^2+2x-1) is 0<= x< 1/3 \lor x> 1/3