What is the domain of (x-1)/(x+1) ?

The domain of (x-1)/(x+1) is x -1

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domain of (x-1)/(x+1)

domain

\frac{x - 1}{x + 1}

x < - 1 or x > - 1

Interval Notation

(- \infty, - 1) \cup (- 1, \infty)

Solution steps

Find undefined (singularity) points:

x = - 1

The function domain

x < - 1 or x > - 1

\frac{x - 1}{( x - 6 ) ( x + 8 )}

x^{2} + 6 x

f (x) = \frac{- 5 x - x ^{3} - 2}{x ^{3} - 3 x ^{2} + 5}

\frac{x + 4}{x ^{2} + 5 x + 4}

f (x) = \frac{5 + x}{- 4 + 2 x}