What is the domain of f(x)= 6/(sqrt(x^2-4)) ?

The domain of f(x)= 6/(sqrt(x^2-4)) is x 2

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domain of f(x)= 6/(sqrt(x^2-4))

domain

f (x) = \frac{6}{x ^{2} - 4}

x < - 2 or x > 2

Interval Notation

(- \infty, - 2) \cup (2, \infty)

Solution steps

Find non-negative values for radicals:

x \leq - 2 or x \geq 2

Find undefined (singularity) points:

x = 2, x = - 2

Combine real regions and undefined points for final function domain

x < - 2 or x > 2

f (x) = \frac{4 x + 13}{- 3 x}

14

lo g_{5} (3 - x) + 2

f (x) = \frac{x}{x ^{2} + 4}

\frac{7 x}{8 x - 3}

What is the domain of f(x)= 6/(sqrt(x^2-4)) ?
The domain of f(x)= 6/(sqrt(x^2-4)) is x<-2\lor x>2