What is the inverse of f(x)=x^2-7x ?

The inverse of f(x)=x^2-7x is (7+sqrt(49+4x))/2 ,(7-sqrt(49+4x))/2

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inverse of f(x)=x^2-7x

inverse

f (x) = x^{2} - 7 x

\frac{7 + 49 + 4 x}{2}, \frac{7 - 49 + 4 x}{2}

Solution steps

y = x^{2} - 7 x

Replace

x

with

y

x = y^{2} - 7 y

Solve for

y, x = y^{2} - 7 y

\frac{7 + 49 + 4 x}{2}, \frac{7 - 49 + 4 x}{2}

f (x) = \frac{x}{5} - \frac{3}{5}

- \frac{2}{5} x + 4

f (x) = 2 4 - x

f (x) = 5 - x - x^{2} - 9

f (x) = - 2 x^{2}

What is the inverse of f(x)=x^2-7x ?
The inverse of f(x)=x^2-7x is (7+sqrt(49+4x))/2 ,(7-sqrt(49+4x))/2