What is the domain of f(x)=sqrt(x^2-3x+2) ?

The domain of f(x)=sqrt(x^2-3x+2) is x = 2

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domain of f(x)=sqrt(x^2-3x+2)

domain

f (x) = x^{2} - 3 x + 2

x \leq 1 or x \geq 2

Interval Notation

(- \infty, 1] \cup [2, \infty)

Solution steps

Find non-negative values for radicals:

x \leq 1 or x \geq 2

The function domain

x \leq 1 or x \geq 2

x^{\frac{2}{3}}

\frac{X ^{2} + 6}{X ^{2} - 2 X + 15}

3 lo g_{2} (x)

f (x) = - 0.5 x^{2} + 7 x - 4

f (x) = - x^{2} + 3

What is the domain of f(x)=sqrt(x^2-3x+2) ?
The domain of f(x)=sqrt(x^2-3x+2) is x<= 1\lor x>= 2