What is the critical (x^2-3)/(x^2-7) ?

The critical (x^2-3)/(x^2-7) is x=0

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critical (x^2-3)/(x^2-7)

critical points

\frac{x ^{2} - 3}{x ^{2} - 7}

x = 0

Solution steps

\frac{x ^{2} - 3}{x ^{2} - 7}

Find where

f^{'} (x)

is equal to zero or undefined

x = 0, x = - 7, x = 7

Identify critical points not in

f (x)

domain

Domain of

\frac{x ^{2} - 3}{x ^{2} - 7} : x < - 7 or - 7 < x < 7 or x > 7

\frac{x ^{2} - 3}{x ^{2} - 7}

is not defined at

x = - 7, x = 7

, therefore:

x = 0

arccsc (\frac{1}{4}) x

f (x) = 2 arccos (x + 1) + \frac{π}{2}

\frac{1}{1 - x ^{2}}

\frac{2 x ^{2} - 12 x + 16}{x ^{2} - x - 12}

(x - 3)^{2} + 7