What is the range of f(x)=sqrt((x-2)) ?

The range of f(x)=sqrt((x-2)) is f(x)>= 0

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range of f(x)=sqrt((x-2))

range

f (x) = (x - 2)

f (x) \geq 0

Interval Notation

[0, \infty)

Solution steps

The range of an radical function of the form

c a x + b + k

f (x) \geq k

k = 0

f (x) \geq 0

f (x) = 1 - x^{2}

f (x) = \frac{x}{2} + 9

\frac{x ^{2} - 1}{x + 1}

f (x) = \frac{1}{3} (x - 1)

f (x) = (\frac{- 58 x + 265}{- 16 x + 64})

What is the range of f(x)=sqrt((x-2)) ?
The range of f(x)=sqrt((x-2)) is f(x)>= 0