What is the inverse of f(x)=sqrt(1-x^2) ?

The inverse of f(x)=sqrt(1-x^2) is sqrt(-x^2+1),-sqrt(-x^2+1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=sqrt(1-x^2)

inverse

f (x) = 1 - x^{2}

- x^{2} + 1, - - x^{2} + 1

Solution steps

y = 1 - x^{2}

Replace

x

with

y

x = 1 - y^{2}

Solve for

y, x = 1 - y^{2}

- x^{2} + 1, - - x^{2} + 1

f (x) = \frac{x}{2} + 9

\frac{x ^{2} - 1}{x + 1}

f (x) = \frac{1}{3} (x - 1)

f (x) = (\frac{- 58 x + 265}{- 16 x + 64})

f (x) = \frac{4}{x ^{2} + 1}

What is the inverse of f(x)=sqrt(1-x^2) ?
The inverse of f(x)=sqrt(1-x^2) is sqrt(-x^2+1),-sqrt(-x^2+1)