What is the domain of f(x)=sqrt(1/3 (x-1)) ?

The domain of f(x)=sqrt(1/3 (x-1)) is x>= 1

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domain of f(x)=sqrt(1/3 (x-1))

domain

f (x) = \frac{1}{3} (x - 1)

x \geq 1

Interval Notation

[1, \infty)

Solution steps

Find non-negative values for radicals:

x \geq 1

The function domain

x \geq 1

f (x) = (\frac{- 58 x + 265}{- 16 x + 64})

f (x) = \frac{4}{x ^{2} + 1}

f (x) = 6 x^{2} + 9

\frac{x - 1}{x ^{2}}

f (x) = \frac{( x + 1 )}{2 x + 1}

What is the domain of f(x)=sqrt(1/3 (x-1)) ?
The domain of f(x)=sqrt(1/3 (x-1)) is x>= 1