What is the range of f(x)= x/(sqrt(x+1)) ?

The range of f(x)= x/(sqrt(x+1)) is -infinity <f(x)<infinity

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

range of f(x)= x/(sqrt(x+1))

range

f (x) = \frac{x}{x + 1}

- \infty < f (x) < \infty

Interval Notation

(- \infty, \infty)

Solution steps

Find the minimum and maximum value in each defined interval and unite the results

Domain of

\frac{x}{x + 1} : x > - 1

Extreme Points of

\frac{x}{x + 1} :

None

Find the range for the interval

- 1 < x < \infty : - \infty < f (x) < \infty

Combine the ranges of all domain intervals to obtain the function range

- \infty < f (x) < \infty

f (x) = 3 x^{4} - 8 x^{3} + 8

f (x) = x^{2} - 6 x + 4

f (x) = \frac{x + 4}{5 - 3 x}

f (x) = \frac{3 x - 5}{7}

x + 3

What is the range of f(x)= x/(sqrt(x+1)) ?
The range of f(x)= x/(sqrt(x+1)) is -infinity <f(x)<infinity