What is the shift 1/2 sin(4t-2pi) ?

The shift 1/2 sin(4t-2pi) is Phase: pi/2 , Vertical:0

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shift 1/2 sin(4t-2pi)

shift

\frac{1}{2} sin (4 t - 2 π)

Phase : \frac{π}{2}, Vertical : 0

Solution steps

f (x) = \frac{1}{2} sin (4 t - 2 π)

g (B x - C) = sin (4 t - 2 π), B = 4, C = 2 π, D = 0

Therefore, the phase shift

\frac{C}{B}

\frac{2 π}{4}

\frac{π}{2}

The vertical shift

D

0

0

f (x) = 2 cos (6 x + \frac{π}{2})

(250, - 200), (350, - 500)

\frac{- 6 + 3 x ^{2}}{x ^{2} - 1}

f (x) = 5 x + 3

12 x + 3 y = - 3

What is the shift 1/2 sin(4t-2pi) ?
The shift 1/2 sin(4t-2pi) is Phase: pi/2 , Vertical:0