What is the inverse of f(x)= 1/6 x^3-5 ?

The inverse of f(x)= 1/6 x^3-5 is cube root of 6x+30

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)= 1/6 x^3-5

inverse

f (x) = \frac{1}{6} x^{3} - 5

Solution steps

y = \frac{1}{6} x^{3} - 5

Replace

x

with

y

x = \frac{1}{6} y^{3} - 5

Solve for

y, x = \frac{1}{6} y^{3} - 5

\frac{8 x - 3}{x}

x^{2} + 2 x + 1

3 x - 4 y = - 40

f (x) = x - 7

f (x) = \frac{x}{x ^{2} + 1}

What is the inverse of f(x)= 1/6 x^3-5 ?
The inverse of f(x)= 1/6 x^3-5 is cube root of 6x+30