What is the domain of g(x)=(5x+1)/(x^2-16x+63) ?

The domain of g(x)=(5x+1)/(x^2-16x+63) is x 9

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domain of g(x)=(5x+1)/(x^2-16x+63)

domain

g (x) = \frac{5 x + 1}{x ^{2} - 16 x + 63}

x < 7 or 7 < x < 9 or x > 9

Interval Notation

(- \infty, 7) \cup (7, 9) \cup (9, \infty)

Solution steps

Find undefined (singularity) points:

x = 9, x = 7

The function domain

x < 7 or 7 < x < 9 or x > 9

\frac{4}{- x - 6}

- \frac{1}{2 9 - x}

2 x^{3} + x

f (x) = x - 2 - x

(2, 1), (2, - 2)

What is the domain of g(x)=(5x+1)/(x^2-16x+63) ?
The domain of g(x)=(5x+1)/(x^2-16x+63) is x<7\lor 7<x<9\lor x>9