What is the asymptotes of y=(2x^2+10x+12)/(x^2+3x+2) ?

The asymptotes of y=(2x^2+10x+12)/(x^2+3x+2) is Vertical: x=-1,Horizontal: y=2

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asymptotes of y=(2x^2+10x+12)/(x^2+3x+2)

asymptotes

y = \frac{2 x ^{2} + 10 x + 12}{x ^{2} + 3 x + 2}

Vertical : x = - 1, Horizontal : y = 2

Solution steps

Vertical asymptotes of

\frac{2 x ^{2} + 10 x + 12}{x ^{2} + 3 x + 2} : x = - 1

Horizontal Asymptotes of

\frac{2 x ^{2} + 10 x + 12}{x ^{2} + 3 x + 2} : y = 2

Slant Asymptotes of

\frac{2 x ^{2} + 10 x + 12}{x ^{2} + 3 x + 2} :

None

Vertical : x = - 1, Horizontal : y = 2

f (x) = e^{- 5 t}

3 x - y = 1, (3, 8)

f (x) = (x - 2) (x + 3)

- \frac{4 x}{16 - x ^{2}}

x - \frac{108}{x ^{2}}

What is the asymptotes of y=(2x^2+10x+12)/(x^2+3x+2) ?
The asymptotes of y=(2x^2+10x+12)/(x^2+3x+2) is Vertical: x=-1,Horizontal: y=2