en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

f(x)=x^2+x+1

Solution

f (x) = x^{2} + x + 1

Solution

Domain : - \infty < x < \infty

Range : f (x) \geq \frac{3}{4}

Y Intercepts : (0, 1)

Vertex : Minimum (- \frac{1}{2}, \frac{3}{4})

Inverse : \frac{- 1 + 4 x - 3}{2}, \frac{- 1 - 4 x - 3}{2}

+1

Interval Notation

Domain : (- \infty, \infty)

Range : [\frac{3}{4}, \infty)

Solution steps

Domain of

x^{2} + x + 1 : - \infty < x < \infty

Range of

x^{2} + x + 1 : f (x) \geq \frac{3}{4}

Axis interception points of

x^{2} + x + 1 :

Y Intercepts

: (0, 1)

Vertex of

x^{2} + x + 1 :

Minimum

(- \frac{1}{2}, \frac{3}{4})

Inverse of

x^{2} + x + 1 : \frac{- 1 + 4 x - 3}{2}, \frac{- 1 - 4 x - 3}{2}

Popular Examples

inverse of f(x)=8-2x^3 inverse

f (x) = 8 - 2 x^{3}

inverse of f(x)= 1/(2x+4)inverse

f (x) = \frac{1}{2 x + 4}

inverse of ((e^x))/(1+9e^x)inverse

\frac{( e ^{x} )}{1 + 9 e ^{x}}

domain of f(x)=sqrt(16-3x)domain

f (x) = 16 - 3 x

inverse of f(x)=(x-7)^3 inverse

f (x) = (x - 7)^{3}

Frequently Asked Questions (FAQ)

What is the f(x)=x^2+x+1 ?
The f(x)=x^2+x+1 is