What is the perpendicular 3x+y=4,(7,8) ?

The perpendicular 3x+y=4,(7,8) is y= 1/3 x+17/3

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perpendicular 3x+y=4,(7,8)

perpendicular

3 x + y = 4, (7, 8)

y = \frac{1}{3} x + \frac{17}{3}

Solution steps

Find the line

y = mx + b

perpendicular to

3 x + y = 4

that passes through

(7, 8)

Find the slope of

3 x + y = 4 : m = - 3

Compute the slope of the perpendicular line:

m_{p} = \frac{1}{3}

Find the line with slope m=

\frac{1}{3}

and passing through

(7, 8) : y = \frac{1}{3} x + \frac{17}{3}

y = \frac{1}{3} x + \frac{17}{3}

t + 9

5 x + 9 + 1

y - 9 = \frac{1}{5} (x - 2)

- 3 x - y = 2

\frac{4 x + 11}{5 x - 6}

What is the perpendicular 3x+y=4,(7,8) ?
The perpendicular 3x+y=4,(7,8) is y= 1/3 x+17/3