What is the shift-6cos(-4x-pi/8) ?

The shift-6cos(-4x-pi/8) is Phase:-pi/(32), Vertical:0

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shift-6cos(-4x-pi/8)

shift

- 6 cos (- 4 x - \frac{π}{8})

Phase : - \frac{π}{32}, Vertical : 0

Solution steps

f (x) = - 6 cos (- 4 x - \frac{π}{8})

g (B x - C) = cos (- 4 x - \frac{π}{8}), B = - 4, C = \frac{π}{8}, D = 0

Therefore, the phase shift

\frac{C}{B}

\frac{\frac{π}{8}}{- 4}

- \frac{π}{32}

The vertical shift

D

0

0

\frac{4 x}{x ^{2} - 25}

f (x) = \frac{49}{x ^{2} - x}

f (x) = x^{\frac{4}{5}} (x - 5)^{2}

f (x) = - x - 1 + 3

\frac{4 x ^{2} - 16 x + 17}{x ^{2} - 4 x + 4}

What is the shift-6cos(-4x-pi/8) ?
The shift-6cos(-4x-pi/8) is Phase:-pi/(32), Vertical:0