What is the inverse of f(x)=(4x)/(x^2+25) ?

The inverse of f(x)=(4x)/(x^2+25) is (2+sqrt(-25x^2+4))/x ,(2-sqrt(-25x^2+4))/x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=(4x)/(x^2+25)

inverse

f (x) = \frac{4 x}{x ^{2} + 25}

\frac{2 + - 25 x ^{2} + 4}{x}, \frac{2 - - 25 x ^{2} + 4}{x}

Solution steps

y = \frac{4 x}{x ^{2} + 25}

Replace

x

with

y

x = \frac{4 y}{y ^{2} + 25}

Solve for

y, x = \frac{4 y}{y ^{2} + 25}

\frac{2 + - 25 x ^{2} + 4}{x}, \frac{2 - - 25 x ^{2} + 4}{x}

91.1

f (x) = (x - 6)^{2} + 8

f (x) = \frac{12 x - 3}{9 x ^{2} - 4}

\frac{3 x ^{2} - 27}{x ^{2} - 9 x + 18}

arccsc (x + 5)

What is the inverse of f(x)=(4x)/(x^2+25) ?
The inverse of f(x)=(4x)/(x^2+25) is (2+sqrt(-25x^2+4))/x ,(2-sqrt(-25x^2+4))/x