What is the perpendicular 3x-8y=3 ?

The perpendicular 3x-8y=3 is y=-8/3 x+b

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perpendicular 3x-8y=3

perpendicular

3 x - 8 y = 3

y = - \frac{8}{3} x + b

Solution steps

Find the slope of

3 x - 8 y = 3 : m = \frac{3}{8}

Compute the slope of the perpendicular line:

m_{p} = - \frac{8}{3}

Line with slope m=

- \frac{8}{3} : y = - \frac{8}{3} x + b

y = - \frac{8}{3} x + b

\frac{6 x}{x - 8} - \frac{7}{8 - x}

2 x + 2

f (x) = 3 x^{2} - 30 x - 9

f (x) = 2 x - 4 y = - 1

f (x) = \frac{x}{( x + 1 )}