What is the critical f(x)=x^6-3x^4 ?

The critical f(x)=x^6-3x^4 is x=-sqrt(2),x=0,x=sqrt(2)

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critical f(x)=x^6-3x^4

critical points

f (x) = x^{6} - 3 x^{4}

x = - 2, x = 0, x = 2

Solution steps

x^{6} - 3 x^{4}

Find where

f^{'} (x)

is equal to zero or undefined

x = - 2, x = 0, x = 2

Identify critical points not in

f (x)

domain

Domain of

x^{6} - 3 x^{4} : - \infty < x < \infty

All critical points are in domain

x = - 2, x = 0, x = 2

(x + \frac{2}{3})^{2} - 3

\frac{e ^{x^{2} + 1}}{2}

- 5 x - 2 y = 4

x - 8

f (x) = - 2 x^{2}, x \geq 0

What is the critical f(x)=x^6-3x^4 ?
The critical f(x)=x^6-3x^4 is x=-sqrt(2),x=0,x=sqrt(2)