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midpoint
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inverse of y= 1/(x+4)inverse intercepts of f(x)= 1/(x-3)intercepts midpoint (-3,-1),(-4,2)midpoint symmetry y=x^2-2x-35symmetry vertices y=x^2-4x+3vertices
Frequently Asked Questions (FAQ)
What is the midpoint (-9,3),(7,-8) ?
The midpoint (-9,3),(7,-8) is (-1,-5/2)