What is the midpoint (sqrt(3),5sqrt(2)),(-2sqrt(3),-sqrt(2)) ?

The midpoint (sqrt(3),5sqrt(2)),(-2sqrt(3),-sqrt(2)) is (-(sqrt(3))/2 ,2sqrt(2))

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midpoint (sqrt(3),5sqrt(2)),(-2sqrt(3),-sqrt(2))

midpoint

(3, 52), (- 23, - 2)

(- \frac{3}{2}, 22)

Solution steps

Midpoint of

(x_{1}, y_{1}), (x_{2}, y_{2})

(\frac{x _{2} + x _{1}}{2}, \frac{y _{2} + y _{1}}{2})

(x_{1}, y_{1}) = (3, 52), (x_{2}, y_{2}) = (- 23, - 2)

= (\frac{- 2 3 + 3}{2}, \frac{- 2 + 5 2}{2})

Refine

= (- \frac{3}{2}, 22)

- - x - 9

f (x) = x^{2} - 8

\frac{sin ( t ) + t cos ( t )}{cos ( t ) - t sin ( t )}

f (x) = x^{4} - 4 x^{2}

2 cos (6 x + \frac{π}{2})

What is the midpoint (sqrt(3),5sqrt(2)),(-2sqrt(3),-sqrt(2)) ?
The midpoint (sqrt(3),5sqrt(2)),(-2sqrt(3),-sqrt(2)) is (-(sqrt(3))/2 ,2sqrt(2))