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Popular >

distance (5,-3),(6,-5)

Solution

distance

(5, - 3), (6, - 5)

Solution

5

Solution steps

The distance between

(x_{1}, y_{1}), (x_{2}, y_{2})

is:

(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}

The distance between

(5, - 3)

and

(6, - 5)

is

= (6 - 5)^{2} + (- 5 - (- 3))^{2}

Simplify

= 5

Popular Examples

inverse of f(x)= 3/2 x-3/2 inverse

f (x) = \frac{3}{2} x - \frac{3}{2}

inverse of y=5x inverse

y = 5 x

domain of (x+9)/(x^2+7x-18)domain

\frac{x + 9}{x ^{2} + 7 x - 18}

domain of (7(x+9))/(9x)domain

\frac{7 ( x + 9 )}{9 x}

inverse of x^3 inverse

x^{3}

Frequently Asked Questions (FAQ)

What is the distance (5,-3),(6,-5) ?
The distance (5,-3),(6,-5) is square root of 5