What is the inverse of f(x)=((x-2))/((x+3)) ?

The inverse of f(x)=((x-2))/((x+3)) is (-2-3x)/(x-1)

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inverse of f(x)=((x-2))/((x+3))

inverse

f (x) = \frac{( x - 2 )}{( x + 3 )}

\frac{- 2 - 3 x}{x - 1}

Solution steps

y = \frac{x - 2}{x + 3}

Replace

x

with

y

x = \frac{y - 2}{y + 3}

Solve for

y, x = \frac{y - 2}{y + 3}

\frac{- 2 - 3 x}{x - 1}

g (x) = 7 - x

(11 - t)^{6}

f (x) = x - \frac{4}{x}

f (x) = e^{\frac{1}{x}}

f (x) = arccos (e^{x})

What is the inverse of f(x)=((x-2))/((x+3)) ?
The inverse of f(x)=((x-2))/((x+3)) is (-2-3x)/(x-1)