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midpoint
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critical f(x)=(x^2+8x-4)/(x-2)critical points domain of (x-3)/(x+3)domain domain of f(x)=sqrt(6x^2+7x-5)domain domain of f(x)=log_{3}(x-1)+0.239784domain inverse of f(x)= 1/(1+x^2)inverse
Frequently Asked Questions (FAQ)
What is the midpoint (-5/2 , 3/2),(-11/2 ,-15/2) ?
The midpoint (-5/2 , 3/2),(-11/2 ,-15/2) is (-4,-3)