What is the inverse of f(x)=sqrt((x^2+5x)) ?

The inverse of f(x)=sqrt((x^2+5x)) is (-5+sqrt(25+4x^2))/2 ,(-5-sqrt(25+4x^2))/2

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inverse of f(x)=sqrt((x^2+5x))

inverse

f (x) = (x^{2} + 5 x)

\frac{- 5 + 25 + 4 x ^{2}}{2}, \frac{- 5 - 25 + 4 x ^{2}}{2}

Solution steps

y = x^{2} + 5 x

Replace

x

with

y

x = y^{2} + 5 y

Solve for

y, x = y^{2} + 5 y

\frac{- 5 + 25 + 4 x ^{2}}{2}, \frac{- 5 - 25 + 4 x ^{2}}{2}

f (x) = 2 x^{2} - 5 x - 3

(6, 3), (- 6, - 9)

f (x) = 3 cos (\frac{π}{10} t)

f (x) = \frac{7}{x ^{3} - 1}

(0.6, - 0.2), (3.1, 1.4)

What is the inverse of f(x)=sqrt((x^2+5x)) ?
The inverse of f(x)=sqrt((x^2+5x)) is (-5+sqrt(25+4x^2))/2 ,(-5-sqrt(25+4x^2))/2