What is the domain of (4t^2-9)/(8t+16) ?

The domain of (4t^2-9)/(8t+16) is t -2

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domain of (4t^2-9)/(8t+16)

domain

\frac{4 t ^{2} - 9}{8 t + 16}

t < - 2 or t > - 2

Interval Notation

(- \infty, - 2) \cup (- 2, \infty)

Solution steps

Find undefined (singularity) points:

t = - 2

The function domain

t < - 2 or t > - 2

\frac{x}{- x - 2}

y = 2 x^{3} - 3 x^{2} - 12 x + 7

- x + 12

x^{3}

What is the domain of (4t^2-9)/(8t+16) ?
The domain of (4t^2-9)/(8t+16) is t<-2\lor t>-2