What is the inverse of f(x)=x^2+3,x>= 0 ?

The inverse of f(x)=x^2+3,x>= 0 is sqrt(x-3),-sqrt(x-3)

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inverse of f(x)=x^2+3,x>= 0

inverse

f (x) = x^{2} + 3, x \geq 0

x - 3, - x - 3

Solution steps

y = x^{2} + 3

Replace

x

with

y

x = y^{2} + 3

Solve for

y, x = y^{2} + 3

x - 3, - x - 3

f (x) = 12 - x^{2}

f (x) = x (x + 2) (x - 3)

f (x) = \frac{2 x}{x - 8}

f (x) = x^{3} + 3 x^{2} - 9 x - 4

f (x) = x^{3} + 2 x^{2} - 9 x - 18

What is the inverse of f(x)=x^2+3,x>= 0 ?
The inverse of f(x)=x^2+3,x>= 0 is sqrt(x-3),-sqrt(x-3)