What is the perpendicular 6x+3y=-6 ?

The perpendicular 6x+3y=-6 is y= 1/2 x+b

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perpendicular 6x+3y=-6

perpendicular

6 x + 3 y = - 6

y = \frac{1}{2} x + b

Solution steps

Find the slope of

6 x + 3 y = - 6 : m = - 2

Compute the slope of the perpendicular line:

m_{p} = \frac{1}{2}

Line with slope m=

\frac{1}{2} : y = \frac{1}{2} x + b

y = \frac{1}{2} x + b

f (x) = \frac{1 + 4 x}{2 x - 1}

(10.3) (4.7)

12 x^{2} - 204 x + 594

y = 0.25 x - 7, (- 6, 8)

f (x) = - 3 x + 8