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Popular >

distance (1,-7),(-4,-5)

Solution

distance

(1, - 7), (- 4, - 5)

Solution

29

Solution steps

The distance between

(x_{1}, y_{1}), (x_{2}, y_{2})

is:

(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}

The distance between

(1, - 7)

and

(- 4, - 5)

is

= (- 4 - 1)^{2} + (- 5 - (- 7))^{2}

Simplify

= 29

Popular Examples

asymptotes of (-x+4)/(2x+3)asymptotes

\frac{- x + 4}{2 x + 3}

range of 3/((x-2)(x+2))range

\frac{3}{( x - 2 ) ( x + 2 )}

critical sin^2(x)critical points

sin^{2} (x)

extreme f(x)=x^3-12x+5 extreme points

f (x) = x^{3} - 12 x + 5

inverse of f(x)=sqrt(x^2+5x),x>0 inverse

f (x) = x^{2} + 5 x, x > 0

Frequently Asked Questions (FAQ)

What is the distance (1,-7),(-4,-5) ?
The distance (1,-7),(-4,-5) is square root of 29