What is the range of f(x)=|3x-5|+1 ?

The range of f(x)=|3x-5|+1 is f(x)>= 1

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range of f(x)=|3x-5|+1

range

f (x) = ∣ 3 x - 5 ∣ + 1

f (x) \geq 1

Interval Notation

[1, \infty)

Solution steps

The range of an absolute function of the form

c ∣ a x + b ∣ + k

f (x) \geq k

k = 1

f (x) \geq 1

f (x) = e^{14 x - 15}

f (x) = \frac{x + 7}{x - 3}

f (x) = \frac{4 x}{( 2 x + 3 )}

6 x + 2 y = 4

g (x) = - \frac{3}{5} x + \frac{12}{5}