What is the inverse of f(x)= 4/3 (x-1)^3+6 ?

The inverse of f(x)= 4/3 (x-1)^3+6 is \sqrt[3]{(3x-18)/4}+1

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inverse of f(x)= 4/3 (x-1)^3+6

inverse

f (x) = \frac{4}{3} (x - 1)^{3} + 6

Solution steps

y = \frac{4}{3} (x - 1)^{3} + 6

Replace

x

with

y

x = \frac{4}{3} (y - 1)^{3} + 6

Solve for

y, x = \frac{4}{3} (y - 1)^{3} + 6

f (x) = \frac{( x + 13 )}{x - 10}

f (x) = 3 x^{\frac{2}{3}} - x

(- 1.6), (- 4.1)

3 x + 15 y = - 135

12 x - 3 y - 12 = 0

What is the inverse of f(x)= 4/3 (x-1)^3+6 ?
The inverse of f(x)= 4/3 (x-1)^3+6 is \sqrt[3]{(3x-18)/4}+1