What is the domain of 1/(\frac{4){x-1}-2} ?

The domain of 1/(\frac{4){x-1}-2} is x 3

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domain of 1/(\frac{4){x-1}-2}

domain

\frac{1}{\frac{4}{x - 1} - 2}

x < 1 or 1 < x < 3 or x > 3

Interval Notation

(- \infty, 1) \cup (1, 3) \cup (3, \infty)

Solution steps

Find undefined (singularity) points:

x = 3, x = 1

The function domain

x < 1 or 1 < x < 3 or x > 3

\frac{x ^{2} + 2 x}{- 4 x + 8}

f (x) = - x^{3} + 3 x^{2} + 10 x

- \frac{x}{2} - \frac{5}{2} - y = 0

f (x) = - \frac{1}{2} (x + 3)

f (x) = - 2 sin (\frac{2}{3} x - \frac{π}{6})

What is the domain of 1/(\frac{4){x-1}-2} ?
The domain of 1/(\frac{4){x-1}-2} is x<1\lor 1<x<3\lor x>3