What is the domain of f(x)=sqrt(x+6)+sqrt(8-x) ?

The domain of f(x)=sqrt(x+6)+sqrt(8-x) is -6<= x<= 8

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domain of f(x)=sqrt(x+6)+sqrt(8-x)

domain

f (x) = x + 6 + 8 - x

- 6 \leq x \leq 8

Interval Notation

[- 6, 8]

Solution steps

Find non-negative values for radicals:

- 6 \leq x \leq 8

The function domain

- 6 \leq x \leq 8

\frac{- 5 x - 5}{3 x - 5}

y = 4 x - 2

f (x) = ln (\frac{π}{x}) + arctan (2 x)

f (x) = x^{4} - 18 x^{2}

f (x) = \frac{x ^{2}}{9 x ^{2} + 8 x - 1}

What is the domain of f(x)=sqrt(x+6)+sqrt(8-x) ?
The domain of f(x)=sqrt(x+6)+sqrt(8-x) is -6<= x<= 8