What is the inverse of f(x)=\sqrt[3]{6x-4}+2 ?

The inverse of f(x)=\sqrt[3]{6x-4}+2 is (x^3-6x^2+12x-4)/6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

inverse of f(x)=\sqrt[3]{6x-4}+2

inverse

\frac{x ^{3} - 6 x ^{2} + 12 x - 4}{6}

Solution steps

Replace

x

with

y

Solve for

\frac{x ^{3} - 6 x ^{2} + 12 x - 4}{6}

f (x) = 3 + (8 + x)^{\frac{1}{2}}

f (x) = y + 3

f (x) = - \frac{3}{5} x + 6

- 2 cos (2 x + \frac{π}{3})

x^{4} + 2 x^{3} - 12 x^{2} + 1

What is the inverse of f(x)=\sqrt[3]{6x-4}+2 ?
The inverse of f(x)=\sqrt[3]{6x-4}+2 is (x^3-6x^2+12x-4)/6