What is the vertices y=10x^2 ?

The vertices y=10x^2 is Minimum (0,0)

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vertices y=10x^2

vertices

y = 10 x^{2}

Minimum (0, 0)

Solution steps

y = 10 x^{2}

The parabola parameters are:

a = 10, b = 0, c = 0

x_{v} = - \frac{b}{2 a}

x_{v} = - \frac{0}{2 \cdot 10}

Simplify

x_{v} = 0

Plug in

x_{v} = 0

to find the

y_{v}

value

y_{v} = 0

Therefore the parabola vertex is

(0, 0)

a < 0,

then the vertex is a maximum value

a > 0,

then the vertex is a minimum value

a = 10

Minimum (0, 0)

f (x) = cos (x - \frac{π}{2})

(2 - x^{2}) (x^{2} - 9)

f (x) = \frac{4}{x ^{2} - 4 x}

f (x) = \frac{5 x + 1}{9 x - 2}