What is the inverse of f(x)=-3x^2+7 ?

The inverse of f(x)=-3x^2+7 is sqrt(-(x-7)/3),-sqrt(-(x-7)/3)

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inverse of f(x)=-3x^2+7

inverse

f (x) = - 3 x^{2} + 7

- \frac{x - 7}{3}, - - \frac{x - 7}{3}

Solution steps

y = - 3 x^{2} + 7

Replace

x

with

y

x = - 3 y^{2} + 7

Solve for

y, x = - 3 y^{2} + 7

- \frac{x - 7}{3}, - - \frac{x - 7}{3}

f (x) = \frac{1 + e ^{x}}{1 - e ^{x}}

- 25 x + 1000

f (x) = 2 sin (x) cos (x)

y = ln (\frac{e}{x})

y = 2 x - 3, (- 7, - 2)

What is the inverse of f(x)=-3x^2+7 ?
The inverse of f(x)=-3x^2+7 is sqrt(-(x-7)/3),-sqrt(-(x-7)/3)